Answer:
[tex]50\sqrt{2}\: feet[/tex]
Step-by-step explanation:
In the coordinate plane, two of the vertices of Square C are (1, 5) and (11, 15).
The length of the diagonal of Square C is the straight line joining the two points.
Using the distance formula in coordinate geometry:
[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\(x_1,y_1)=(1, 5) ,(x_2,y_2)= (11, 15)\\Distance=\sqrt{(11-1)^2+(15-5)^2} =\sqrt{10^2+10^2} =\sqrt{200}\\Distance=10\sqrt{2}[/tex]
On the graph,
1 square Unit =25 Square Feet
1 Unit =5 feet.
Therefore:
Length of the diagonal of square C
[tex]=5*10\sqrt{2}\\=50\sqrt{2}\: feet[/tex]
