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A compound (C7H14O) has a strong peak in it’s IR spectrum at 1710 cm-1. It’s 1H NMR spectrum consists of only three singlets in the ratio 9:3:2 at δ = 1.0, 2.1, 2.3 ppm respectively. Identify the compound.

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Answer:

Explanation:

The IR spectrum at 1710 cm⁻¹ illustrates how stretched the carbonyl group is:

The name of the  carbonyl compound is: 4,4-dimethyl-2-pentanone.

For the identification of the compound, check the attached word document below.

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