Answer:
C. Yes, and it is highly probable.
Explanation:
Null hypothesis, [tex]H_0[/tex] : ц 0.09
Alternative hypothesis, [tex]H_1[/tex]: ц > 0.09
Test statistic is,
x Z = x - ц / s
[tex]\frac{0.15 - 0.09 }{0.06}[/tex]
[tex]\frac{0.06}{0.06}[/tex]
=1
The p-value is,
p = P(Z > z)
=1—P(Z ≤1)
= 1— 0.841345
= 0.158655
(From normal tables)
The p-value is greater than the significance level, so we fail to reject the null hypothesis. The correct option is, C
Yes, and it is highly probable.