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Find fq, the vertical force that pier q exerts on the right end of the bridge. express the vertical force at q in terms of m and g

Respuesta :

lublana

Answer:

[tex]F_Q=\frac{Mg}{3}[/tex]

Explanation:

We are given that

Length of beam=L

Mass of object=M

We have to find the FQ , the  vertical force that pier exerts on the right end of the bridge .

Torque about P

[tex]F_Q(3L)-MgL=0[/tex]

[tex]F_Q(3L)=MgL[/tex]

[tex]F_Q=\frac{MgL}{3L}[/tex]

[tex]F_Q=\frac{Mg}{3}[/tex]

Hence, the force that exerted pier Q exerts on the right end  of the bridge is given by

[tex]F_Q=\frac{Mg}{3}[/tex]

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