Kaylee invested $910 in an account paying an interest rate of 2.6% compounded
quarterly. Assuming no deposits or withdrawals are made, how much money, to the
nearest dollar, would be in the account after 10 years?

Respuesta :

qop

Answer:

$1,179

Step-by-step explanation:

Lets use the compound interest formula provided to solve this:

[tex]A=P(1+\frac{r}{n} )^{nt}[/tex]

P = initial balance

r = interest rate (decimal)

n = number of times compounded annually

t = time

First, lets change 2.6% into a decimal:

2.6% -> [tex]\frac{2.6}{100}[/tex] -> 0.026

Since the interest is compounded quarterly, we will use 4 for n. Lets plug in the values now:

[tex]A=910(1+\frac{0.026}{4})^{4(10)}[/tex]

[tex]A=1,179.21[/tex]

The account balance after 10 years will be $1,179

Answer:

A≈1179

Step-by-step explanation: