Answer:
Step-by-step explanation:
Let represent the edge of the tank with x and the radius of the first sphere with x/2;
The amount of the water = Volume of the tank - Volume of the sphere
= [tex]x^3 - \frac{4}{3} \pi (\frac{x}{2})^3[/tex]
on the second cube ; the radius of the sphere = [tex]\frac{x}{4} \ units[/tex] ;
Also the number of sphere here is = 8
The amount of water = [tex]x^3 -8*\frac{4}{3} \pi (\frac{x}{4})^3[/tex]
For the third figure ; the radius of the sphere is = [tex]\frac{x}{8} \ units[/tex]
Also the number of sphere here is = 64
The amount of water = [tex]x^6 -64*\frac{4}{3} \pi (\frac{x}{8})^3[/tex]
= [tex]x^3 - \frac{4}{3} \pi (\frac{x}{2})^3[/tex]
In the fourth tank ; 512 sphere illustrates that in a single row; that more than one 8 sphere is present i.e 8³ = 512
then the radius will be = [tex]\frac{x}{16}[/tex]
The amount of water = [tex]x^3 -512*\frac{4}{3} \pi (\frac{x}{16})^3[/tex]
= [tex]x^3 -\frac{4}{3} \pi (\frac{x}{2})^3[/tex]
This implies that alll the three cube shaped tanks are identical and hold equal amount of water.
