Respuesta :

Answer:

(10, 0.205π)

Step-by-step explanation:

The magnitude of the coordinates is:

[tex]\|\vec r \| = \sqrt{8^{2}+6^{2}}[/tex]

[tex]\|\vec r \| = 10[/tex]

Besides, the angle associated with the coordinates is:

[tex]\theta = \tan^{-1}\left(\frac{6}{8} \right)[/tex]

[tex]\theta = 0.205\pi[/tex]

The polar coordinates are (10, 0.205π)