Answer:
The number of pages Gillian wrote on the third day is [tex]2\frac{1}{6}[/tex] pages
Step-by-step explanation:
Given
Number of days = 3 days
Pages of report = 10 pages
First day = 3½ pages
Second day = 4⅓ pages
Required
Number of pages written on the third day.
Let the number of pages written on the first, second and the third day be represented with F, S and T respectively.
So,
F = 3½ pages
S = 4⅓ pages
From the given data, we have that the report was 10 pages.
Hence,
F + S + T = 10 pages
F + S + T = 10
By substitution, we have
3½ + 4⅓ + T = 10
Convert mixed fractions to equivalent improper fraction.
[tex]\frac{7}{2} + \frac{13}{3} + T = 10[/tex]
Add fractions
[tex]\frac{21 + 26}{6} + T = 10[/tex]
[tex]\frac{47}{6} + T = 10[/tex]
Make T the subject of formula
[tex]T = 10 - \frac{47}{6}[/tex]
Subtract
[tex]T = \frac{60 - 47}{6}[/tex]
[tex]T = \frac{13}{6}[/tex]
[tex]T = 2\frac{1}{6}[/tex]
Recall that T represent number of pages written on the third day.
Hence, the number of pages Gillian wrote on the third day is [tex]2\frac{1}{6}[/tex] pages
