Answer:
0.0332 M
Explanation:
Step 1:
The balanced equation for the reaction.
KOH + HC2H302 -> KC2H302 + H2O
From the balanced equation above,
The mole ratio of the acid (nA) = 1
The mole ratio of the base (nB) = 1
Step 2:
Data obtained from the question.
Volume of base (Vb) = 15.98 mL
Molarity of base (Mb) = 0.1080 M
Volume of acid (Va) = 52.00 mL
Molarity of acid (Ma) =?
Step 3:
Determination of the molarity of the acid.
Using the formula:
MaVa/MbVb = nA/nB
The molarity of the acid can be obtained as follow
MaVa/MbVb = nA/nB
Ma x 52 / 0.1080 x 15.98 = 1
Cross multiply to express in linear form
Ma x 52 = 0.1080 x 15.98
Divide both side by 52
Ma = (0.1080 x 15.98) /52
Ma = 0.0332 M
Therefore, the molarity of the acid solution is 0.0332 M
