contestada

A student needs to dilute a 0.31 M Pb(NO3)2 solution to make 83.0 mL of 0.19 M Pb(NO3)2 . Set up the calculation by placing the values with the correct units into the equation. Then, calculate the volume, in milliliters, of the 0.31 M Pb(NO3)2 solution that is needed.

Respuesta :

Answer : The volume, in milliliters, of the 0.31 M [tex]Pb(NO_3)_2[/tex] solution that needed is, 50.9 mL

Explanation :

Formula used :

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1\text{ and }V_1[/tex] are the initial molarity and volume of dilute [tex]Pb(NO_3)_2[/tex].

[tex]M_2\text{ and }V_2[/tex] are the final molarity and volume of [tex]Pb(NO_3)_2[/tex].

We are given:

[tex]M_1=0.31M\\V_1=?\\M_2=0.19M\\V_2=83.0mL[/tex]

Putting values in above equation, we get:

[tex]0.31M\times V_1=0.19M\times 83.0mL\\\\V_1=50.9mL[/tex]

Hence, the volume, in milliliters, of the 0.31 M [tex]Pb(NO_3)_2[/tex] solution that needed is, 50.9 mL

Otras preguntas