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Write the equation of a line that is perpendicular to x=−6x, and that passes through the point (−1,−2)

Respuesta :

Answer:

Step-by-step explanation:

y=-6x

slope=-6

slope of line ⊥ to given line=1/6

eq. of reqd. line is

y+2=-1/6 (x+1)

6y+12=-(x+1)

or

6y+12=-x-1

6y+x=-1-12

or 6y+x=-13

Answer:

y=-2

Step-by-step explanation:

Answer from Khanacademy

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