ovoxoclovd
ovoxoclovd
31-07-2016
Mathematics
contestada
what is the value of k?
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dalendrk
dalendrk
31-07-2016
[tex]6^9\cdot6^x=6^2\ \ \ |use\ a^m\cdot a^n=a^{m+n}\\\\6^{9+x}=6^2\iff9+x=2\ \ \ |subtract\ 9\ from\ both\ sides\\\\\boxed{x=-7}[/tex]
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princegn
princegn
31-07-2016
6^9 . 6^x = 6^2
6^(9+x) = 6^2
9+x = 2
x = 2 - 9
x = -7
Answer Link
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