swajid217
swajid217
27-07-2016
Mathematics
contestada
Value of x in log5x = 4logx5 is
Respuesta :
Аноним
Аноним
27-07-2016
log5 x=4 logx 5
Ln x/ln5=4(ln5 / ln x) logx z=ln x / ln z
least common multiple=ln5 * ln x
ln²x=4ln²5
√(ln² x)=√(4 ln²5)
ln x=2ln 5
x=e^2ln5=25
Answer: x=25.
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