Respuesta :

konrad509
[tex]y = \ln (5x)\\ e^y=5x\\ x=\dfrac{e^y}{5}\\ \boxed{f^{-1}(x)=\dfrac{e^x}{5}}[/tex]



dalendrk
[tex]f(x)=\ln5x\\\\\ln5x=y\\\\e^{\ln5x}=e^y\iff5x=e^y\ \ \ |divide\ both\ sides\ by\ 5\\\\x=\dfrac{e^y}{5}\\\\\boxed{f^{-1}(x)=\dfrac{e^x}{5}}[/tex]

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