Answer:
Kp = 24.8
Explanation:
[tex]2CO_{2(g)}[/tex] ⇄ [tex]2CO + 0_{(2g)}[/tex]
1.00 0 0
1.0-2x 2x x
x = 2.1%
[tex]= 1 X \frac{2.1}{100}[/tex]
= 0.021
[tex]P_{co_{2}} = 1- 2 X 0.021[/tex]
=0.958 atm
[tex]P_{co = 0.042 atm[/tex]
[tex]P_{o_{2}} = 0.021 atm[/tex]
[tex]Kp = \frac{[CO_{2} ]^{2} }{[CO]^{2} [O_{2} ] }[/tex]
[tex]Kp = \frac{[0.958 ]^{2} }{[0.042]^{2} [0.021] }[/tex]
=[tex]\frac{0.917}{(1.76 X 10^{-3} ) (0.021 )}[/tex]
=0.917/0.0000369
=24.8
