Using the cumulative distribution table, it is found that the correct option is:
E. No, the distribution is skewed to the right with mean less than 4 movies.
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From the table, the distribution is:
[tex]P(X = 1) = 0.2[/tex]
[tex]P(X = 2) = 0.3[/tex]
The above is because:
[tex]P(X \leq 2) = 0.5[/tex]
[tex]P(X \leq 1) + P(X = 2) = 0.5[/tex]
[tex]0.2 + P(X = 2) = 0.5[/tex]
[tex]P(X = 2) = 0.3[/tex]
Applying the same for the other values:
[tex]P(X = 3) = 0.1[/tex]
[tex]P(X = 4) = 0.1[/tex]
[tex]P(X = 5) = 0.1[/tex]
[tex]P(X = 6) = 0.1[/tex]
[tex]P(X = 7) = 0.1[/tex]
The expected value is each value multiplied by it's probability, so:
[tex]E(X) = 1(0.2) + 2(0.3) + 3(0.1) + 4(0.1) + 5(0.1) + 6(0.1) + 7(0.1) = 3.3[/tex]
- The mean is 3.3, less than 4.
- At least 60% of the values are below the mean, thus, the distribution is right-skewed, which means that the correct option is:
E. No, the distribution is skewed to the right with mean less than 4 movies.
A similar problem is given at https://brainly.com/question/16914931