Answer:
132 g
Explanation:
Given data:
Mass of silver nitrate react = 260 g/100×80 = 208 g
Mass of silver metal produced = ?
Solution:
Chemical equation:
Cu + 2AgNO₃ → 2Ag + Cu(NO₃)₂
Number of moles of AgNO₃:
Number of moles = mass/molar mass
Number of moles = 208 g/ 169.87 g/mol
Number of moles = 1.22 mol
Now we will compare the moles of silver with solver nitrate from balance chemical equation.
AgNO₃ : Ag
2 : 2
1.22 ; 1.22
Mass of Ag:
Mass = number of moles × molar mass
Mass = 1.22 mol × 107.8682 g/mol
Mass = 132 g
