Answer: 16 g of [tex]O_{2}[/tex] reacted with the magnesium
Explanation:
from the equation of reaction: 2Mg + [tex]O_{2}[/tex]→[tex]2MgO[/tex]
48g of Mg requires 32g of O2 to yield 80g of MgO
That is :
48 : 32 : 80
Hence 12 : x: 32
xg of O2 =[tex]\frac{12(32)}{48}[/tex]
= 16 g of [tex]O_{2}[/tex]
Therefore:
16 g of [tex]O_{2}[/tex] reacted with the magnesium
