Answer:
The current throught the wire has a value of 15 A.
Explanation:
We can use Ohm's second law to find the resistance of the wire and then use his first law to find the current in it.
Ohm's second law is given by:
R = (p*l)/A
Where R is the resistance of the wire, A is the area of the cross-sectional, l is the length of the wire and p is the resistivity of the material.
R = [1*5.6*10^(-8)]/(0.86*10^(-6)) = 6.51*10^(-2) Ohms
Ohm's first law is given by:
I = V/R
Where I is the current through the wire, V is the voltage drop across it's terminals and R is it's resistance. We have:
I = 0.97/[6.51*10^(-2)] = 0.15*10^(2) A = 15 A
The current throught the wire has a value of 15 A.
