Answer: The partial pressure of the water vapor is 1.108 atm
Explanation:
According to Dalton's law, the total pressure of a mixture of gases is the sum of individual pressures exerted by the constituent gases.
[tex]p_{total}=p_A+p_B[/tex]
Thus [tex]p_{total}=p_{N_2}+p_{H_2O}[/tex]
Given: [tex]p_{total}[/tex] =4.015 atm
[tex]p_{N_2}[/tex]= 2.907 atm
[tex]p_{H_2O}[/tex] = ?
Thus [tex]4.015=2.907+p_{H_2O}[/tex]
[tex]p_{H_2O}=1.108atm[/tex]
Thus the partial pressure of the water vapor is 1.108 atm
