contestada

When sodium metal is added to water, the following reaction occurs: 2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g) What is the theoretical number of moles of hydrogen gas produced when 0.068 mol of sodium metal reacts?

Respuesta :

sebassandin

Answer:

[tex]n_{H_2}^{Theoretical}=0.034molH_2[/tex]

Explanation:

Hello,

In this case, based on the given rewritten reaction:

[tex]2Na(s) + 2H_2O(l) \rightarrow 2NaOH(aq) + H_2(g)[/tex]

The stoichiometry leads to the following theoretical moles of oxygen:

[tex]n_{H_2}^{Theoretical}=0.068molNa*\frac{1molH_2}{2molNa}=0.034molH_2\\n_{H_2}^{Theoretical}=0.034molH_2[/tex]

As sodium and hydrogen as a 2 to 1 molar relationship.

Best regards.

Otras preguntas