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Define function print_popcorn_time() with parameter bag_ounces. If bag_ounces is less than 3, print "Too small". If greater than 10, print "Too large". Otherwise, compute and print 6 * bag_ounces followed by "seconds". End with a newline. Sample output with input: 7 42 seconds

Respuesta :

ijeggs

Answer:

def print_popcorn_time(bag_ounces):

 if bag_ounces<3:

   print("Too Small")

 elif bag_ounces>10:

   print("Too Large")

 else:

   bag_ounces = bag_ounces*6

   print("%s Seconds\n" % bag_ounces)    

Explanation:

  • Using Python Programming Language
  • The function is defined to accept an int parameter
  • Within the function body, if...elif and else statements are used to print the desired output
  • note the use of the %s placeholder (formated output) and \n for a new line in the final print statement
rossrebecca58

Answer:

The other answer had some mistakes (i.e. capitalization when it should be lower case, etc.) that made it incorrect. Here is the updated answer:

Written in Python:

def print_popcorn_time(bag_ounces):

if bag_ounces<3:

  print("Too small")

elif bag_ounces>10:

  print("Too large")

else:

  bag_ounces = bag_ounces*6

  print("%s seconds" % bag_ounces)

 

user_ounces = int(input())

print_popcorn_time(user_ounces)

Explanation:

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