Answer:
( 11.7 , 12.7 )
Step-by-step explanation:
The provided information is:
Sample mean = [tex]\bar{X} = 12.2[/tex]
Standard deviation = [tex]\sigma=1.6[/tex]
Sample size = n = 49
Significance level = [tex]\alpha=0.05[/tex]
Thus, the 95% confidence interval is:
[tex]\bar{X}\pm Z_{\alpha/2}\frac{\sigma}{\sqrt{n}}\\=12.2\pm Z_{0.05/2}\frac{1.6}{\sqrt{49}}\\=12.2\pm 1.96\times0.2286\\=12.2\pm 0.4480\\=(11.7.12.7)[/tex]