Answer:
(a) The current should be in opposite direction
(b) The current needed is 39.8 A
Explanation:
Part (a)
Based, on right hand rule, the current should be in opposite direction
Part (b)
given;
strength of magnetic field, B = 370 µT
distance between the two parallel wires, d = 8.6 cm
[tex]B = \frac{\mu_oI}{2\pi R}[/tex]
At the center, the magnetic field strength is twice
[tex]B_c = 2(\frac{\mu_oI}{2\pi R}) =\frac{ \mu_oI}{\pi R}[/tex]
R = d/2 = 8.6/2 = 4.3 cm = 0.043 m
[tex]B_c = \frac{ \mu_oI}{\pi R}\\\\I = \frac{B_c\pi R}{\mu_o} = \frac{370 *10^{-6}* \pi *0.043}{4\pi *10^{-7}}\\\\I = 39.8 \ A[/tex]
Therefore, current needed is 39.8 A
