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A projectile of mass 0.50 kg is fired with an initial speed of 10 m/s at an angle of 60 degrees above the horizontal. The potential energy of the projectile-Earth system when the projectile is at its highest point (relative to the potential energy when the projectile is at ground level) is:

Respuesta :

Answer:

 U=18.75 J

Explanation:

given that

Mass ,m = 0.5 kg

Initial velocity , u= 10 m/s

angle, θ = 60°

The maximum height in the projectile motion h is given as follows

[tex]h=\dfrac{u^2sin^2\theta}{2g}[/tex]

[tex]h=\dfrac{10^2sin^{2}60^{\circ}}{2\times 10}\ m[/tex]

h=3.75 m

The potential energy is given as

U = m g h

U= 0.5 x 10 x 3.75 J

U=18.75 J

Therefore the potential energy at the highest point will be 18.75 J.

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