Respuesta :
Answer:
The mass of the block of ice is 90.91 kg.
Explanation:
The expression for the equation of motion is as follows;
[tex]s=ut+\frac{1}{2}at^2[/tex]
Here, u is the initial speed, a is the acceleration, t is the time and s is the distance.
Calculate the acceleration of the given block.
[tex]s=ut+\frac{1}{2}at^2[/tex]
Put t= 5 s, s= 11 m and u= 0 in the above expression.
[tex]11=(0)t+\frac{1}{2}a(5)^2[/tex]
[tex]a= 0.88 ms^{-2}[/tex]
The expression for the force in terms of mass and acceleration is as follows;
F= ma
Here, F is the force and m is the mass.
Put F= 80 N and [tex]a= 0.88 ms^{-2}[/tex].
80= m(0.88)
m=90.91 kg
Therefore, the mass of the block of ice is 90.91 kg.
