Answer:
787.5 V/m
Explanation:
the formula to find the electric field in the region between the plates is
E = V/d
where
V=the voltage supplied by the battery (potential)
d=distance between the plates.
E=electric field
Given:
V= 6.3 V
d= 1.6cm/2=> 0.016m/2
E= V/d=> 6.3/(0.016/2)
E= 787.5 V/m
Therefore, the electric field in the region between the plates is 787.5 V/m
Answer:
The electric field in the region between the plates is 787.5 V/m
Explanation:
The magnitude of the potential difference between the plates is equal to the product of the magnitude of the electric field and the distance between the plates.
The relationship:
[tex]E=\frac{V}{d}[/tex]
Electric field: [tex]E[/tex] is unknown
Voltage supplied: [tex]V=6.3volts[/tex]
distance between the plates: [tex]d=\frac{16cm}{2} =\frac{0.016m}{2}=0.008m[/tex]
[tex]E=\frac{V}{d}[/tex]
Now substitute the values
[tex]E=\frac{6.3V}{0.008m} \\E=787.5V/m[/tex]
The electric field in the region between the plates is 787.5 V/m.
