Step-by-step explanation:
The mean and standard deviation are:
μ = p
σ = √(pq/n)
Given p = 0.12, q = 0.88, and n = 200:
μ = 0.12
σ = √(0.12 × 0.88 / 200)
σ = 0.023
Since the sample is large, it can be approximated with a normal distribution. Find the z-score:
z = (x − μ) / σ
z = (0.14 − 0.12) / 0.023
z = 0.87
Use a calculator or table to find the probability:
P(Z > 0.87) = 1 − 0.8078
P(Z > 0.87) = 0.1922
