Respuesta :
Answer:
high pitch with a short wavelength
Explanation:
"Pitch" refers to how high or low the sound is. This is determined by the sound's frequency.
"Wavelength" refers to the distance that is being traveled by the wave before another wave starts.
Remember that a higher frequency requires a shorter wavelength because the time between the repetitions is decreased. This also means that the lower the frequency, the longer the wavelength.
A dog's whistle is 23-54 kHz, which is beyond what the human ear can grasp. When you look at the frequency, it is higher than 20 kHz, thus the frequency is higher which means the pitch is high. Such high pitch is coupled with a shorter wavelength, as mentioned earlier.
So, this explains the answer.
Answer:
high pitch with a short wavelength
Explanation:
When we talk about waves, we can describe them using several properties:
- Frequency: the frequency of a wave is the number of complete oscillations of the wave per second.
- Wavelength: the wavelength of a wave is the distance between two consecutive points of the wave having same shape - for instance, the distance between two consecutive crests
- Pitch: it is a property describing "how high" it is a sound wave in terms of frequency - so basically it is proportional to the frequency
Moreover, wavelength is inversely proportional to the frequency, according to
[tex]\lambda=\frac{v}{f}[/tex]
where
[tex]\lambda[/tex] is the wavelength
v is the speed of the wave
f is the frequency
In the problem, we see that the sound waves produced by the dog whistle have a frequency (23-54 kHz) much higher than the human range (<20 kHz). So, these sound waves have:
- Higher frequency
- Higher pitch
- Shorter wavelength
So the correct answer is
high pitch with a short wavelength