A fast ferry takes 4 hours to cross a lake an average speed of 108km/h. On a particular day, it travaled at an average speed of 94km/h for 4 hours. What was the remaining distance?

Respuesta :

Answer:

Remaining distance will be 56 km

Explanation:

As we know that the distance traveled is given as the product of speed and time

So we will have

[tex]d = v \times t[/tex]

so total distance to cross is given as

[tex]d_{total} = 4\times 108[/tex]

[tex]d_{total} = 432 km[/tex]

Now if it moves with speed of 94 km/h for 4 hours then distance covered by it

[tex]d = 94 \times 4[/tex]

[tex]d = 376 km[/tex]

Remaining distance is given as

[tex]d_{remain} = d_{total} - d[/tex]

[tex]d_{remain} = 432 - 376 [/tex]

[tex]d_{remain} = 56 km[/tex]

The remaining distance will be "56 km".

Speed and Time:

The speed (s) of an object seems to be the rate at which it travels from one location to some other. It's also calculated by dividing the distance (d) traveled by the timeframe (t) or duration.

According to the question,

Average speed when cross a late, 108 km/h

On particular day, average speed 94 km/h

Time taken, 4 hours

We know that,

Distance, d = v × t

The total distance be:

→ [tex]d_{total}[/tex] = 4 × 108

           = 432 km

When it moves 94 km/h, the distance be;

→ d = 94 × 4

      = 376 km

hence,

The remaining distance be:

→ [tex]d_{remain}[/tex] = [tex]d_{total}[/tex] - d

By substituting the values,

               = 432 - 376

               = 56 km

Thus the above answer is correct.

Find out more information about speed here:

https://brainly.com/question/4931057