Answer:
53.3J
Explanation:
Given parameters:
Mass of object = 4kg
Initial velocity = 3m/s
Final velocity = 6m/s
time taken = 8s
Unknown:
Amount of work done on body = ?
Solution:
Work done is the force applied to move a body through a particular distance.
Work done = force x distance
let us find force and distance:
Using newton's second law of motion:
F = ma
where m is the mass and a is the acceleration
First find the acceleration;
Acceleration = [tex]\frac{V- u}{t}[/tex]
V is the initial velocity
U is the final velocity
Input the parameters;
a = [tex]\frac{6-3}{8}[/tex] = 0.38m/s²
F = 4 x 0.38 = 1.5N
To find the distance;
V² = U² + 2as
where s is the distance
6² = 3² + 2(0.38)s
s = 35.5m
Work done = 1.5 x 35.5 = 53.3J
