Answer:
Any point that is 5 units from the center
Step-by-step explanation:
The given circle is centered at;
(-3,-1) and contains (1,2).
The radius is given by:
[tex]r = \sqrt{(x_2-x_1)^2 +(y_2-y_1)^2} [/tex]
We substitute the point to get:
[tex]r = \sqrt{(1- - 3)^2 +(2- - 1)^2} [/tex]
[tex]r = \sqrt{4^2 +3^2} [/tex]
[tex]r = \sqrt{25} = 5[/tex]
Therefore any point that is 5 units from the center lies on this circle.
