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What are the zeros of the function f(x) = x2 + 8x + 4, expressed in simplest radical form? x = –4 ± 2StartRoot 3 EndRoot x = –4 ± StartRoot 48 EndRoot x = StartFraction negative 8 plus or minus StartRoot 3 EndRoot Over 2 End Fraction x = StartFraction negative 4 plus or minus 4 StartRoot 3 EndRoot Over 2 End Fraction

Respuesta :

Answer:

x = -4 ± 2√(3)  

Step-by-step explanation:

Discriminant Δ = √(8²-4×(1)×(4)) = √(48) = √(4×12) = √(4)×√(12) = 2√(12)

then x = (-8 ± 2√(12))÷2 = -4 ±√(12) = -4 ±√(3×4) = -4 ± 2√(3)  

Answer:

A. on edg

Step-by-step explanation:

Just took the assignment.

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