Respuesta :

Answer:

use sin2A as 2sinAcosA and solve

Answer:

Inconclusive

Explanation:

Sin2A= Sin(A+A)= SinACosA + CosAsinA=2SinACosA

Similarly

Sin2B= 2SinBCosB

Sin2C=2SinCCosC

Adding all; we cannot arrive at the expression at the right.