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skyluke89

Answer:

Short circuit

Explanation:

An inductor works on the principle of electromagnetic induction.

When a current passes through an inductor, a magnetic field is generated inside it; if the magnitude of this magnetic field changes, then according to Faraday-Newmann-Lenz law, an emf (electromotive force) is induced in the inductor itself, according to:

[tex]\epsilon=-\frac{d\Phi}{dt}[/tex]

where [tex]\Phi[/tex] is the magnetic flux linkage through the inductor. Therefore, as a result of this induced emf, a current is also induced in the inductor, and the direction of this current is such that it opposes to the change in magnetic flux linkage.

Therefore, the intensity of this current depends on the rate of change of magnetic flux linkage through the inductor.

If we have a DC (direct current), then the current in the inductor is steady; as a result, its magnetic field is also steady, and therefore, there is no change in magnetic flux, so no induced current. Therefore, the inductor will oppose no resistance to the flow of original current, and so it can be approximated to a short circuit (zero resistance).

Martebi

The  reasonable approximation for an inductor at DC steady is one that states that;

  • At steady state we are said  to assumed that inductor will be short circuit which implies that voltage across the inductor is zero.
  • At steady state we say or see that capacitor is open circuited which implies that current through capacitor is zero.

The action that occurs when inductor at steady state condition in DC circuit is that due to the steady state of the DC current flowing via the inductor, there is therefore a zero induced voltage that is seen across it.

The inductor is known to acts as kind of short circuit that equal to a piece of wire.

Learn more about short circuit from

https://brainly.com/question/25018411

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