Answer:
247.9 g
Explanation:
First, convert mass to moles.
215.8 g Ag (1 mol Ag / 107.9 g Ag) = 2.00 mol Ag
32.1 g S (1 mol S / 32.1 g S) = 1.00 mol S
Find the limiting reactant (if there is one):
2.00 mol Ag (1 mol S / 2 mol Ag) = 1.00 mol S
There is no limiting reactant (both reactants completely react). So use either reactant to find moles of product.
2.00 mol Ag (1 mol Ag₂S / 2 mol Ag) = 1.00 mol Ag₂S
Convert moles to mass:
1.00 mol Ag₂S (247.9 g Ag₂S / mol Ag₂S) = 247.9 g Ag₂S
