Answer:
Explanation:
The electrons will also spiral with frequency of 42 x 10⁶
n = 42 x 10⁶
For circular motion of electron
= Bqv = m ω² r ( centripetal force )
v / r = m ω² / Bq
= 4π² n² m / Bq
T = 2πr / v
1 / n = 2πr / v
r / v = 1 / 2π n
2π n = ω²m / Bq
ω = ω² m/ Bq
B = ω m / q
B = 2π nm / q
= 2 x 3.14 x 42 x 10⁶ x 9.1 x 10⁻³¹ / 1.6 x 10⁻¹⁹
= 15 x 10⁻⁴ T
