Toretto and O’Conner graphed two different quadratic functions in vertex form. Toretto graphed f(x)=(x+3)^2+1 and O’Conner graphed g(x) =-(x-3)^2+1 . Both of them drew the same graph.

Toretto and OConner graphed two different quadratic functions in vertex form Toretto graphed fxx321 and OConner graphed gx x321 Both of them drew the same graph class=

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By observing the graph we can say that minimum value of Toretto graph occurs at x=-3

whereas the minimum value of OConner graph occurs at x=3 .

In the given figure the minimum value is at x=3

therefore OConner is correct because the vertex is (3,1)

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Answer:

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Step-by-step explanation: