lilDot88
lilDot88
28-06-2016
Mathematics
contestada
12
∑ 20(0.5)^n-1
n=3
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nobillionaireNobley
nobillionaireNobley
30-06-2016
Assuming n starts from 1.
∑[tex]20 (0.5)^{n-1}[/tex]; n = 1 to 3
[tex]=20 (0.5)^{1-1}+20 (0.5)^{2-1}+20 (0.5)^{3-1} \\ =20 (0.5)^{0}+20 (0.5)^{1}+20 (0.5)^{2} \\ =20(1)+20(0.5)+20(0.25) \\ =20+10+5 \\ =35[/tex]
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