Go to your periodic table and look up the elements and add up for the compounds.
I = 127, Kr = 84, NH₃ = 17, C₁₀H₁₆O = 152, CH₂O = 30
A)
I₂ = 2* I = 2*127 g/mol = 254 g/mol, 4.6 mol = 4.6 * 254 = 1168.4 g
B) 4.1 mol of NH₃ = 4.1 * 17 = 69.7
C) 0.39 mol of C₁₀H₁₆O = 0.39 * 152 = 59.28g
D) 1.8 mol of CH₂O = 1.8*30 = 54g
E) 9.2 mol of Kr = 9.2 * 84 = 772.8g
The largest as you can see is A.
A. 4.6 mol of iodine vapor, I₂
