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Assume that genes A and B are not linked. If the probability of allele A in a gamete is 1/2 and the probability of allele B in a gamete is 1/2, then the probability that both A and B are in the same gamete is

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Answer:

P(A and B) = 1/4

Step-by-step explanation:

Since A and B are not linked. The event is said to be independent events:

Therefore;

P(A and B) = P(A) × P(B)

Where; P(A and B) is the probability that both A and B are in the same gamete.

P(A) = 1/2 => Probability of allele A in the gamete

P(B) = 1/2 => Probability of allele B in the gamete

Thus,

P(A and B) = P(A) × P(B) = (1/2) * (1/2) = 1/4 = 0.25.

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