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The heat of combustion of butane is 2877.5 kJ/mol how much heat in calories will be produced in the combustion of 100.0 g of butane?

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hadangcap

Answer:

The answer is 1,185,000 cal or 1,185 kcal

Explanation:

We convert the weight of butane (C₄H₁₀, MW = 58) to mole

n = m/M = 100.0 / 58 = 1.724 mol

The heat of combustion of 100.0 g or 1.724 mol of butane is

H(kJ) = 1.724 mol  x 2,877.5 kJ/mol = 4,960.8 kJ

Then we convert the unit to calories

H(cal) = 4,960.8 kJ / 4.184 kJ/kcal = 1,185 kcal = 1,185,000 cal

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