11. Density of the piece of wood = 3000 g/cm³
12. Density of wooden block = 2 g/cm³. and it will not float in water.
13. Volume of the plastic ball should be 250 mL
14. Mass of the ice cube = 0.162 g
15. Volume of gasoline spilled is equal to 2000 mL
Explanation:
11.
Formula: [tex]Density = \frac{Mass}{Volume}[/tex]
Given:
Mass of wood piece = 7500 g
Volume of wood piece = 2.5 cm³
Therefore, [tex]Density = \frac{7500\ g}{2.5\ cm^{3} } = 3000\ g/cm^{3}[/tex]
Density of the piece of wood = 3000 g/cm³
12.
Formula: [tex]Density = \frac{Mass}{Volume}[/tex]
Given:
Dimensions of wooden block = length × width × height = 5 cm × 4 cm × 2 cm
Mass = 80.0 g
Volume of wooden block = [tex]L\times W\times H = 5\times 4\times 2 = 40 cm^3[/tex]
Therefore, [tex]Density = \frac{80\ g}{40\ cm^{3} } = 2\ g/cm^{3}[/tex]
Density of wooden block = 2 g/cm³.
Density of water is equal to 1 g/cm³
2 g/cm³ > 1 g/cm³
Since density of wooden block is greater than the density of water, the piece of wood will not float in water. It will sink.
13.
Formula: [tex]Volume= \frac{Mass}{Density}[/tex]
Given:
Mass of the ball = 125 g
Density = 0.5 g/mL
Therefore, [tex]Volume = \frac{125\ g}{0.5\ g/mL } = 250\ mL[/tex]
Volume = 250 mL
Volume of the plastic ball should be 250 mL
14.
Formula: [tex]Mass = Density\times Volume[/tex]
Given:
Dimensions of ice cube = length × width × height = 3 cm × 3 cm × 3 cm
Density = 0.006 g/mL
Volume of ice cube = [tex]L\times W\times H = 3\times 3\times 3 = 27\ cm^3[/tex]
Since,
[tex]1\ cm^3 = 1\ mL,\\\\ Volume = 27\ mL[/tex]
Therefore, [tex]Mass = (0.006\ g/mL)\times (27\ mL) = 0.162\ g[/tex]
Mass of the ice cube = 0.162 g.
15.
Formula: [tex]Volume= \frac{Mass}{Density}[/tex]
Given:
Mass of gasoline = 1330 g
Density = 0.665 g/mL
Therefore, [tex]Volume = \frac{1330\ g}{0.665\ g/mL } = 2000\ mL[/tex]
Volume = 2000 mL
Volume of gasoline spilled is equal to 2000 mL
