Answer:
68
Step-by-step explanation:
Given:
sample mean u = 50.36
standard deviation δ = 1.58
Assuming measurements x follows a normal distribution as follows:
X - N ( u , δ^2 ) -- > X - N ( 50.36 , 2.4964 )
The probability of next measurement being 2 δ from mean u :
P ( u - δ < X < u + δ ) -----> P ( 48.78 < X < 51.94 )
Compute z-score and corresponding probability values:
P ( 48.78 < X < 51.94 ) = P ( (48.78 - 50.36) / 1.58 < z < (51.94 - 50.36) / 1.58 )
P ( 48.78 < X < 51.94 ) = P ( -1 < z < 1 ) = 0.68