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A 45.0 kg ice skater stands at rest on the ice. A friend tosses the skater a 5.0 kg ball. The skater and the ball then move backwards across the ice with a speed of 0.5 m/s. What was the speed of the ball at the moment just before the skater caught it?

Respuesta :

Answer:

u = 5 m/s

Explanation:

given,

Mass of ice skater, M = 45 Kg

initial speed = 0 m/s

mass of the ball, m = 5 Kg

velocity of skater and the ball,V = 0.5 m/s

speed of the ball = ?

using conservation of momentum

m u + M u' =( M + m ) V

initial speed of ice skater is zero

5 x u + 45 x 0 =( 45 + 5 ) V

5 u = 50 x 0.5

5 u = 25

u = 5 m/s

hence, the speed of the ball is equal to 5 m/s

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