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A farmer grows 81 acres of a crop that requires 35 inches (net) of irrigation per year. Water costs $68 per acre-ft in this area. What would the annual water cost be if the irrigation efficiency is 71%?

Respuesta :

Answer:

$22,626.76

Step-by-step explanation:

Data provided in the question:

Area of the crop = 81 acres

Height of water required in the field = 35 inches = 2.9167 ft      [ 1 ft = 12 in]

Cost of water = $68 per acre-ft

Irrigation efficiency = 71%

Now,

Total amount of consumed by the crop = Area of the crop × Height of water

= 81 acres × 2.9167 ft  

= 236.25 acre-ft

Also,

irrigation efficiency = Water consumed ÷ Water supplied

or

0.71 = 236.25 acre-ft ÷ Water supplied

or

Water supplied = 332.75  acre-ft

Therefore,

Cost of water required = Water supplied × Cost of water

= 332.75  × 68

= $22,626.76

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