Answer:
69000 V
Explanation:
E = Electric field = [tex]3\times 10^6\ V/m[/tex]
d = Distance between plates = 2.3 cm
When we multiply the electric field strength and the distance between the plates of a capacitor we get the maximum voltage.
Maximum voltage is given by
[tex]V_m=Ed\\\Rightarrow V_m=3\times 10^6\times 2.3\times 10^{-2}\\\Rightarrow V_m=69000\ V[/tex]
The highest voltage the students can use is 69000 V
