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Suppose two AaBbCc individuals are mated. Assuming that the genes are not linked, what fraction of the offspring are expected to be homozygous recessive for the three traits?a. 1/4 b. 1/8 c. 1/64 d. 1/256e. 1/16

Respuesta :

Answer:c. 1/64

Explanation: A trihybrid(AaBbCc) cross gives a total of 64 possible outcomes.

In the ratio 27:9:9:9:3:3:3:1

A_B_C_ =27

A_B_cc = 9

A_bbC_ =9

A_bbcc =3

aaB_C_=9

aaB_cc =3

aabbC_ =3

aabbcc-1

We just 1 recessive allele produce which is 1 out of 64 i.e 1/64

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