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The volume of 1 kg of helium in a piston-cylinder device is initially 5 m3. Now helium is compressed to 2 m3 while its pressure is maintained constant at 180 kPa. Determine the work required to compress helium, in kJ.

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Answer:

-540 kJ

Explanation:

P = Pressure which is applied to the piston = 180 kPa

[tex]V_2[/tex] = Final volume = 2 m³

[tex]V_1[/tex] = Initial volume = 5 m³

Work done is given by

[tex]W=P\Delta V\\\Rightarrow W=P(V_2-V_1)\\\Rightarrow W=180000(2-5)\\\Rightarrow W=180000\times -3\\\Rightarrow W=-540000\ J\\\Rightarrow W=-540\ kJ[/tex]

The work required to compress helium is -540 kJ