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The fermer is a bone in the leg whose minimum cross-sectional area is about 4.0104m2. A compres-sional force in excess of 6.8104N will fraction thebone. a) Find the maximum stress that this bone canwithstand. b) What is the strain that exists under amaximum stress condition?

Respuesta :

Answer:

a) 1.70N/m^2

b) 4.8 * 10^-6

Explanation:

Parameters given:

Cross sectional area = 4.0104m^2

Maximum Force = 6.8104N

a) Maximum Stress = Maximum Force/Area

Maximum Stress = 6.810/4.0104

Maximum Stress = 1.70N/m^2

b) Strain = Stress/Young's Modulus

Young's modulus of the outer surface of bone has been measured to be  20.7 GPa i.e. 2.07 * 10^7Pa

Strain = 1.7/(2.07 * 10^7)

Strain = 4.8 * 10^-6

 

Strain is dimensionless.

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